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congruent

ADBC

APD ≅ ∠BPC

DAP ≅ ∠BCP

AAS Postulate

APCP

CPCTC

perpendicular

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Given: In Rectangle ABCD, the intersection of the diagonals is point P.
A rectangle is a parallelogram, so opposite sides are parallel and
, making
Vertical angles are congruent, so
.
.
Alternate interior angles formed by a transversal intersecting parallel lines are congruent, so
.
ΔAPD ≅ ΔCBP, because of
.
Therefore, DPBP and
by
.
The diagonals bisect each other by definition of segment bisector.
This deductive argument proves the conjecture correct. Diagonals of a rectangle bisect each other.