One way that you can solve one-variable inequalities is to use a graph or a table.
Consider the situation shown below.
Concert tickets cost $35.50 each, plus a $12 convenience fee. A Spanish Club has a budget of $438 to spend on concert tickets. How many concert tickets, x, can the Spanish Club purchase?
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Linear functions have a constant term, which can be a fixed fee, and a rate of change, or slope. In this situation, what is the fixed fee, and what is the rate charged per ticket?Interactive popup. Assistance may be required.
35.50x + 12 ≤ 438x |
Y1= 35.50x + 12 |
Y2 = 438 |
8 |
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9 |
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10 |
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11 |
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12 |
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13 |
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14 |
You can use an online graphing calculator such as meta-calculator.
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to see instructions on how to use this online calculator to generate a table of values.
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x |
Y1 = 35.50x + 12 |
Y2 = 438 |
8 |
296 |
438 |
9 |
331.5 |
438 |
10 |
367 |
438 |
11 |
402.5 |
438 |
12 |
438 |
438 |
13 |
473.5 |
438 |
14 |
509 |
438 |
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Read down the Y1 and Y2 columns until you see the same number side by side. Interactive popup. Assistance may be required. x = 12Interactive popup. Assistance may be required.
Read the chart upward from x = 12. Would you say that Y1 is less than Y2 or greater than Y2? Interactive popup. Assistance may be required. Y1 < Y2Interactive popup. Assistance may be required.
Read the chart downward from x = 12. Would you say that Y1 is less than Y2 or greater than Y2? Interactive popup. Assistance may be required. Y1 > Y2Interactive popup. Assistance may be required.
Read the chart to identify the x-values where Y1 = Y2 and Y1 < Y2? Interactive popup. Assistance may be required. x ≤ 12How would the possible values for x change if the budget for the Spanish Club had been $367 instead of $438?
Interactive popup. Assistance may be required. The Spanish Club could have spent no more than $367, so change Y2 to 367 and look for the x-values where Y1 ≤ Y2. We can see that x ≤ 10.How would your solution strategy be different if the Spanish Club decided to spend at least $400 on concert tickets?
Interactive popup. Assistance may be required. If the situation were "at least $400," then the inequality would be greater than or equal to $400. Instead of looking for x-values where Y1 ≤ Y2, look for x-values where Y1 ≥ Y2.x |
Y1 |
Y2 |
9 |
-4 |
8 |
10 |
0 |
8 |
11 |
4 |
8 |
12 |
8 |
8 |
13 |
12 |
8 |
14 |
16 |
8 |
15 |
20 |
8 |
Based on the table, what would the solution be to the inequality, 4(x – 10) > 8? Interactive popup. Assistance may be required.
Determine the x-values where Y1 > Y2, but Y1 ≠ Y2.Interactive popup. Assistance may be required.
x > 12x |
Y1 |
3 |
31.82 |
4 |
40.42 |
5 |
49.02 |
6 |
57.62 |
7 |
66.22 |
8 |
74.82 |
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Determine the x-values where Y1 < 49.02, but Y1 ≠ 49.02. Interactive popup. Assistance may be required. x < 5x |
Y1 |
Y2 |
53 |
109.5 |
108 |
53.5 |
110.5 |
109.5 |
54 |
111.5 |
111 |
54.5 |
112.5 |
112.5 |
55 |
113.5 |
114 |
55.5 |
114.5 |
115.5 |
56 |
115.5 |
117 |
Based on the table, what would the solution be to the inequality 2x + 3.5 ≥ 3(x – 17)?
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Determine the x-values where Y1 ≥ Y2. Interactive popup. Assistance may be required. x ≥ 54.5