In lesson 2 of this module we learned how to calculate the mechanical energy

Mechanical Energy:
The sum of the kinetic energy and all forms of potential energy—measured in Joules (J)

Kinetic Energy:
The energy of motion → KE = ½ mv2

Potential Energy:
Stored energy

Gravitational:  Energy stored due to height → PEg = mgh
Elastic:  Energy stored due to compression or stretching → PEs = ½ kx2

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of a system. In this lesson we will concentrate more on how to use mechanical energy to make predictions about how the system will behave.

Once we know the total mechanical energy of a system, there are two possibilities. Either work is done on the system — see lesson 1 of this module—and the total energy changes, or no work is done and the system obeys the Law of Conservation of Energy.

The Law of Conservation of Energy
In a closed isolated system, total mechanical energy is conserved

System:  Group of related objects
Closed:  No mass enters or leaves the system
Isolated:  No unbalanced outside forces—no work done on the system
Conserved:  Stays the same

KEi + PEgi + PEsi = KEf + PEgf + PEsf

In the equation, the subscript i means initial and the subscript f means final

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In the following simulation:
  1. Set the friction slider to 'none.'
  2. Select 'Show Energy of 1.'
  3. Select 1 16 time.'
  4. Use your mouse to add one of the 100 gram masses to the end of spring one.
  5. Stretch the spring so that the mass is almost at the bottom of the screen and then release the mass and watch the values on the graph.

This activity might not be viewable on your mobile device.Interactive exercise. Assistance may be required. Masses and Springs


What happens to the kinetic energy as the mass moves up and down?
Check your answer It is zero at the top and bottom of the mass's path and a maximum in the middle. Close

What happens to the gravitational potential energy as the mass moves up and down?
Check your answer It reaches a maximum at the mass's highest point and a minimum at the mass's lowest point. Close

What happens to the spring potential energy as the mass moves up and down?
Check your answer It is a maximum at the top and bottom of the mass's path and zero in the middle. Close

What happens to the total energy as the mass moves up and down?
Check your answer It stay the same. Close

Example problem 1

A 45 kg child is playing on a swing. At her highest point the swing is 1.75 meters above the ground, and at the lowest point it is 0.45 meters above the ground. How fast is she going at the lowest point?
Hint #1 Conservation of Energy says: KEi + PEgi + PEsi = KEf + PEgf + PEsf Close
Hint #2 There are no springs in this problem, so you can drop PEs out of both sides of the equation:
KEi + PEgi= KEf + PEgf Close

Hint #3 At her highest point, her velocity is zero. Close
Solution Given: m = 45 kg    h1 = 1.75 m    v1 = 0 m/s    h2 = 0.45 m
Unknown: v2 = ?
Equation: KEi + PEgi = KEf + PEgf
½ mv12 + mgh1 = ½ mv22 + mgh2
Simplify:

v1 = 0, so the equation becomes: mgh1 = ½ mv22 + mgh2
The mass cancels from both sides of the equation, so it becomes: gh1 = ½ v22 + gh2
Solve:
gh1 = ½ v22 + gh2
(9.8) (1.75) = ½ v22 + (9.8) (0.45)
17.15 = ½ v22 + 4.41
12.74 = ½ v22
v22 = 25.48
v2 = 5.05 m/s
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Example problem 2

A 2 kg mass is sliding on a table at 3 m/s. It hits the end of a long relaxed spring with spring constant k = 100 N/m. How far will the mass compress the spring before coming to rest?
Hint #1 Conservation of Energy says: KEi + PEgi + PEsi = KEf + PEgf + PEsf Close
Hint #2 There is no change in height in this problem, so PEg drops from both sides of the equation:
KEi + PEsi= KEf + PEsf Close

Hint #3 There are 2 hidden zeros in the problem:
Relaxes spring→xi = 0
Coming to rest→v2 = 0 Close

Solution Given: m = 2 kg    v1 = 3 m/s   k = 100 N/m    x1 = 0m    v2 = 0 m/s
Unknown: x2 = ?
Equation: KEi + PEsi = KEf + PEsf
½ mv12 + ½ kx12 = ½ mv22 + kx22

Simplify:
x1 and v2 are both zero, so the equation becomes: ½ mv12 = kx22
If we multiply both sides by 2, the equation becomes: mv12 = kx22
Solve:
mv12 = kx22
(2)(32) = 100 x22
0.18 = x22
x2 = 0.42 m
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