Another type of relationship you will explore with circles is that of arcs and angles formed by intersecting tangents.

Once again, brainstorm a possible hypothesis to help you guide your thinking. Use what you already know about the relationship between arcs and angles found inside and outside of a circle.

In your notes, write out a prediction in response to the following question:

How will m GJH  and m GH  relate to the angle measure represented by x?

Using the Intersecting Tangents applet linked below, manipulate the endpoints of ADB  so that you always have the red and blue arcs in opposite places on the circle. To change the size of your circle, click and drag point A or point E. Observe the changes in mC as you change the arc measurements.

This activity might not be viewable on your mobile device.Interactive exercise. Assistance may be required. Click on the image below to open the applet. Manipulate the angle so that m ADB  is 240 degrees, then 220 degrees, and finally 200 degrees.

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Copy the table below into your notes. Then use the measures of the arcs to complete the table and answer the questions below.


m C m ADB m AB m ADBm AB
  240°    
  220°    
  200°    

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Pause and Reflect

How does the relationship that you discovered for two intersecting tangents compare to the relationship you discovered for two secants that intersect outside a circle?

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The relationships are very similar in that the measure of the angle of the intersection is equal to one-half the difference of the measures of the intercepted arcs. Close Pop Up


Practice

  1. In circle A below, what is the value of x?

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    The measure of the angle between two tangents from a common point is one-half the difference of the measures of the intercepted arcs. Close Pop Up

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    mBCD = 1 over 2 1 2 (m BKDm BD)
    x = 1 over 2 1 2 (235.7° – 124.3°)
    x = 55.7° Close Pop Up

  2. In circle A below, what is the value of x?

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    The measure of the angle between two tangents from a common point is one-half the difference of the measures of the intercepted arcs. Also, the sum of the measures of the two intercepted arcs is 360°. Close Pop Up

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    Check Your Answer

    mBCD = 1 over 2 1 2 (m BKDm BD)
    First, you need to determine m BKD.
    m BKD + m BD = 360°
    m BKD + 129° = 360°
    m BKD = 231°
    mBCD = 1 over 2 1 2 (m BKDm BD)
    x° = 1 over 2 1 2 (231° – 129°)
    x = 51 Close Pop Up