Now practice by solving the problems below using the method you find the easiest. Use pen and paper to work through the problems. Click on the ????? to check your answers.
| Question | HELP | Answer |
| Given a 6M solution of HNO3, how much is needed to make 2500 mLs of 1.0M nitric acid? | M1V1=M2V2
6M x ? = 1.0M x 2500mL |
416.7 mLS Close |
| What is the molarity of 41.5g of KI dissolved in 800 mLs of water? | M = moles/liters moles = given/molar mass |
0.31m Close |
| What is the molarity of a solution prepared by dissolving 15.0 g of sodium hydroxide in enough water to make a total of 225 mL of solution? | mol NaOH= mol NaOH = 0.375 mol NaOH |
1.67 m NaOH Close |
| What is the molarity of a solution that contains 1.724 moles of H2SO4 in 2.50 L of solution? |
M = 1.724 mol H2SO4 2.50 L soln |
=0.690 M H2SO4 Close |