The solutions to quadratic equations are called roots. Roots are the x-intercepts or zeros of a quadratic function.
For every quadratic equation there is a related quadratic function. For example, if you are given the quadratic equation x2 + 5x + 4 = 0, the related quadratic function is f(x) = x2 + 5x + 4.
A quadratic equation may have two solutions, one solution, or no solution. In this section, you will only learn about quadratics with one or two solutions.
Make a table of values for the function f(x) = x2 – 7x + 6.
x |
f(x) |
0 |
|
1 |
|
4 |
|
6 |
|
7 |
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x |
f(x) |
0 |
6 |
1 |
0 |
4 |
-6 |
6 |
0 |
7 |
6 |
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f(x) = 0Interactive popup. Assistance may be required.
x = 1 and x = 6
Click on the table to see how the value for x, that you have identified, generates the solutions to the equation x2 – 7x + 6 = 0.
How can you identify the solutions to a quadratic equation from a table if the quadratic equation consists of a polynomial that is equal to 0?
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Look for values of the variable (usually x) that generate the function value of 0.If the quadratic equation consists of a polynomial that is equal to b instead of 0, how would you use a table of values to identify the solutions to that equation?
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Look for values of the variable (usually x) that generate the function value of b.Use the tables to determine the zero of each function below. The zero of a function is the root, or solution, to the related equation when the function is equal to 0.
t |
f(t) |
-4 |
8 |
-3 |
0 |
3 |
-6 |
4 |
0 |
5 |
8 |
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The related equation would be the quadratic function when it is set to be equal to 0. Look for function values that are equal to 0.Interactive popup. Assistance may be required.
The roots of the quadratic function, f(t) = t2 – t – 12, are t = 4 and t = −3, which are the t-values of the ordered pairs (4, 0) and (−3, 0) from the table.
0 = 42 – 4 – 12
0 = 16 – 4 – 12
0 = 0
0 = (−3)2 – (−3) – 12
0 = 9 + 3 – 12
0 = 0
x |
f(x) |
-3 |
64 |
-1 |
36 |
0 |
25 |
4 |
1 |
5 |
0 |
6 |
1 |
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The related equation would be the quadratic function when it is set to be equal to 0. Look for function values that are equal to 0.Interactive popup. Assistance may be required.
It appears from the table that the quadratic function, f(x) = x2 – 10x + 25, has only one zero, x = 5, which is the x-value of the ordered pair (5, 0) from the table.
0 = 52 – 10(5) + 25
0 = 25 – 50 + 25
0 = 0
x |
f(x) |
-2 |
3 |
-1 |
0 |
0 |
-1 |
1 |
0 |
2 |
3 |
3 |
8 |
Interactive popup. Assistance may be required.
The related equation would be the quadratic function when it is set to be equal to 0. Look for function values that are equal to 0.Interactive popup. Assistance may be required.
The solutions of the quadratic equation, x2 – 1 = 0, are x = −1 and x = 1, which are the x-values of the ordered pairs (−1, 0) and (1, 0) from the table.
0 = (-1)2 – 1
0 = 1 – 1
0 = 0
0 = 12 – 1
0 = 1 – 1
0 = 0