This section reviews situations where graphing, substitution, and elimination will not find a point of intersection when solving the system of equations.
There are two special cases when solving linear systems of equations.
The first case occurs when solving the systems algebraically. The variables are eliminated, and the left side of the equation does not equal the right side of the equation. Then there is no solution, the lines are parallel.
Example: Solve

-2x + 2y = 6
-x + y = -5
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Multiply the second equation by -2 to create additive inverses:________________.
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- Add the new equation with the first equation:_______________.
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Notice all the variables are inverses of each other resulting in the left side of the equation equaling __________ while the right side's sum is __________.
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The system has _________ solution and the lines are _________.
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The second case occurs when solving the systems algebraically. The variables and the constants are eliminated, and both sides of the equation equal zero. Then any number can be a solution; the lines are coinciding.
Example: Solve

3x – 4y = 12
-6x + 8y = -24
- Multiply the first equation by 2 to create additive inverses:_________________.
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Add the new equation to the second equation:________________.
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- Notice all the variables are inverses of each other, and the left and right sides of the equation both equal ____________.
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The system has _____________ solutions and the lines are ________________.
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